August, 2008
by Adrian Cockcroft
There were some scaling issues with the histograms that needed fixing. Ultimately this made the code look a lot more complex, but it now deals with scaling the plot and the histogram with a fixed zero origin on both axes. It’s important to maintain the zero origin for a throughput vs. response time plot.
The tricky part is that the main plot is automatically oversized from its data range by a few percent and the units used in the histogram are completely different. A histogram with 6 bars is scaled to have the bars at unit intervals and is 6 wide plus the width of the bars etc. After lots of trial and error, the main plot now uses the maximum bucket size of the histogram as its max value and artificially offsets the histograms by what looks like about the right amount. The plot below uses fixed data as a test. Observe that the first bar includes two points-- that’s due to the particular algorithm used by R. Some alternative histogram algorithms are available, but this one seems to be most appropriate to throughput/response time data.
> chp(5:10,5:10)
The updated code follows.
chp <- function(x,y,xl="Throughput",yl="Response",tl="Throughput Over Time", ml="Cockcroft Headroom Plot") { xhist <- hist(x,plot=FALSE) yhist <- hist(y, plot=FALSE) xbf <- xhist$breaks[1] # first ybf <- yhist$breaks[1] # first xbl <- xhist$breaks[length(xhist$breaks)] # last ybl <- yhist$breaks[length(yhist$breaks)] # last xcl <- length(xhist$counts) # count length ycl <- length(yhist$counts) # count length xrange <- c(0,xbl) yrange <- c(0,ybl) nf <- layout(matrix(c(2,4,1,3),2,2,byrow=TRUE), c(3,1), c(1,3), TRUE) layout.show(nf) par(mar=c(5,4,0,0)) plot(x, y, xlim=xrange, ylim=yrange, xlab=xl, ylab=yl) par(mar=c(0,4,3,0)) barplot(xhist$counts, axes=FALSE, xlim=c(xcl*0.03-xbf/((xbl-xbf)/(xcl-0.5)),xcl*0.97), ylim=c(0, max(xhist$counts)), space=0, main=ml) par(mar=c(5,0,0,1)) barplot(yhist$counts, axes=FALSE, xlim=c(0,max(yhist$counts)), ylim=c(ycl*0.03-ybf/((ybl-ybf)/(ycl-0.5)),ycl*0.97), space=0, horiz=TRUE) par(mar=c(2.5,1.7,3,1)) plot(x, main=tl, cex.axis=0.8, cex.main=0.8, type="S") }
[Parts 1 and 2 appeared in the May and July issues respectively.]